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a(n) = n - A326129(n).
4

%I #17 Jul 29 2020 16:39:20

%S 0,1,1,3,1,6,1,7,8,8,1,11,1,10,9,15,1,17,1,19,11,14,1,18,24,16,25,7,1,

%T 18,1,31,15,20,13,35,1,22,17,30,1,30,1,43,41,26,1,47,48,49,21,49,1,42,

%U 17,54,23,32,1,57,1,34,61,63,19,54,1,67,27,66,1,71,1,40,73,73,19,66,1,79,80,44,1,77,23,46,33,86,1,88,21

%N a(n) = n - A326129(n).

%C It seems that A000396 gives all such n for which a(n) = A007913(n).

%H Antti Karttunen, <a href="/A336645/b336645.txt">Table of n, a(n) for n = 1..16384</a>

%H Antti Karttunen, <a href="/A336645/a336645.txt">Data supplement: n, a(n) computed for n = 1..65537</a>

%F a(n) = n - A326129(n) = n - gcd(A326127(n), A326128(n)).

%o (PARI)

%o A326127(n) = (sigma(n)-core(n)-n);

%o A326128(n) = (n-core(n));

%o A336645(n) = (n-gcd(A326127(n), A326128(n)));

%Y Cf. A000203, A000396, A007913, A326126, A326127, A326128, A326129.

%K nonn

%O 1,4

%A _Antti Karttunen_, Jul 29 2020