%I #55 Aug 18 2020 13:10:01
%S 0,3927,7855,11782,15709,19636,23564,27491,31418,35345,39273,43200,
%T 47127,51055,54982,58909,62836,66764,70691,74618,78545,82473,86400,
%U 90327,94255,98182,102109,106036,109964,113891,117818,121745,125673,129600,133527,137455,141382
%N a(n) = time to the nearest second at the nth instant (n>=0) when the hour and minute hands on a clock face coincide, starting at time 0:00.
%C After 12 hours or 43200 seconds, the hands overlap at 12:00 and the cycle repeats.
%H Mathlete's Corner, <a href="https://sites.google.com/site/funproblemsolving/topics1/howmanytimesduringthedaydothehandsofaclockoverlap">How many times during the day do the hands of a clock overlap?</a>
%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (1,0,0,0,0,0,0,0,0,0,1,1).
%F a(n) = round(n*43200/11).
%e For n=1, 3927 would correspond to slightly after 01:05.
%o (SageMath)
%o L=[]
%o n=0
%o while n<50:
%o L.append(round(numerical_approx((n+n/11))*3600))
%o n+=1
%o print(L)
%Y Cf. A120500 (as HHMMSS).
%K nonn
%O 0,2
%A _Sean Lestrange_, Aug 14 2020
