A335655 - OEIS

A335655

Numbers k such that Omega(k+1) = Omega(k) + m, where Omega(k) = A001222(k) is the number of prime factors of k with multiplicity, case m = 3.

%I #15 Jun 26 2021 20:31:54

%S 23,53,59,63,83,89,103,111,119,131,139,149,151,161,197,227,233,293,

%T 299,303,307,347,349,377,379,389,391,395,399,407,443,461,487,491,509,

%U 519,521,539,551,557,563,566,569,571,591

%N Numbers k such that Omega(k+1) = Omega(k) + m, where Omega(k) = A001222(k) is the number of prime factors of k with multiplicity, case m = 3.

%e 23 is in the sequence since Omega(24) = 4 = 1 + 3 = Omega(23) + 3.

%t m = 3; s = {}; Do[If[PrimeOmega[x + 1] == PrimeOmega[x] + m, AppendTo[s, x]], {x, 600}]; s

%Y Cf. A001222, A076156 (case m=1), A335652 (case m=2).

%K nonn

%O 1,1

%A _Zak Seidov_, Jun 16 2020