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Numbers k such that k, k + 1, k + 2 and k + 3 have the same number of divisors in Gaussian integers.
4

%I #4 Feb 09 2020 20:11:13

%S 263449773,334047725,760228973,862305773,1965540624,2136055725,

%T 2362380525,2477365422,2515570575,2613782223,2939626925,3181603023,

%U 3814526223,3987335022,4610697039,4771214574,4981539822,5018728272,5035157775,5186567824,6189727725,6329159823,6569396973

%N Numbers k such that k, k + 1, k + 2 and k + 3 have the same number of divisors in Gaussian integers.

%e 263449773 is a term since 263449773, 263449774, 263449775 and 263449776 each have 72 divisors in Gaussian integers.

%t gaussNumDiv[n_] := DivisorSigma[0, n, GaussianIntegers -> True]; m = 4; s = gaussNumDiv /@ Range[m]; seq = {}; n = m + 1; While[Length[seq] < 10, If[Length @ Union[s] == 1, AppendTo[seq, n - m + 1]]; n++; s = Join[Rest[s], {gaussNumDiv[n]}]]; seq

%Y Cf. A006601, A062327, A332312, A332313.

%K nonn

%O 1,1

%A _Amiram Eldar_, Feb 09 2020