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Numbers k such that the digits of k^(1/8) begin with k.
3

%I #8 Jan 18 2020 18:56:33

%S 0,1,13,192,193,2682,37275,517947,7196856,99999999,100000000,

%T 1389495494,19306977288,268269579527,3727593720314,51794746792311,

%U 51794746792312,719685673001151,719685673001152,9999999999999999,10000000000000000,138949549437313763,1930697728883250166

%N Numbers k such that the digits of k^(1/8) begin with k.

%H Chai Wah Wu, <a href="/A331495/b331495.txt">Table of n, a(n) for n = 1..1111</a>

%e 7196856^(1/8) = 7.1968566387600... which starts with the digits 7196856, so 7196856 is a term.

%Y Cf. A307371, A307588, A307600, A331492, A331493, A331494.

%K nonn,base

%O 1,3

%A _Chai Wah Wu_, Jan 18 2020