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A330146 Number of partitions p of n such that (number of numbers in p that have multiplicity 1) <= (number of numbers in p having multiplicity > 1). 0
1, 0, 1, 1, 3, 4, 7, 9, 13, 16, 24, 29, 39, 51, 69, 87, 118, 152, 199, 256, 330, 418, 534, 670, 838, 1046, 1296, 1603, 1960, 2412, 2936, 3588, 4342, 5288, 6364, 7713, 9272, 11186, 13389, 16117, 19213, 23032, 27408, 32715, 38810, 46176, 54582, 64692, 76286 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,5
COMMENTS
For each partition of n, let
d = number of terms that are not repeated;
r = number of terms that are repeated.
a(n) is the number of partitions such that d <= r.
LINKS
FORMULA
a(n) + A329276(n) = A000041(n) for all n >= 0.
EXAMPLE
The partitions of 6 are 6, 51, 42, 411, 33, 321, 3111, 222, 2211, 21111, 111111.
These have d > r: 6, 51, 42, 321
These have d = r: 411, 3222, 21111
These have d < r: 33, 222, 2211, 111111
Thus, a(6) = 7
MATHEMATICA
z = 30; d[p_] := Length[DeleteDuplicates[Select[p, Count[p, #] == 1 &]]];
r[p_] := Length[DeleteDuplicates[Select[p, Count[p, #] > 1 &]]]; Table[Count[IntegerPartitions[n], p_ /; d[p] <= r[p]], {n, 0, z}]
CROSSREFS
Sequence in context: A004652 A061568 A146994 * A295069 A349360 A103054
KEYWORD
nonn,easy
AUTHOR
Clark Kimberling, Feb 03 2020
STATUS
approved

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Last modified April 16 12:05 EDT 2024. Contains 371711 sequences. (Running on oeis4.)