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Least number m > 0 such that A101337(m)/m = n, or 0 if no such m exists.
3

%I #13 Nov 18 2019 17:56:53

%S 1,459,3194922,174961,119564,0,13598

%N Least number m > 0 such that A101337(m)/m = n, or 0 if no such m exists.

%C Subsequence of A306360, therefore also finite.

%F a(n) = min { m in A306360 | A101337(m)/m = n }.

%o (PARI) {A329292=vector(vecmax(A329291),k, iferr(for(i=1,#A329291, A329291[i]==k&&error(k=A306360[i])),E,k))} \\ If A329291 is not complete, there may be erroneous 0's

%Y Cf. A329291, A101337, A306360.

%K nonn,fini,full

%O 1,2

%A _M. F. Hasler_, Nov 17 2019

%E a(6)-a(7) from _Chai Wah Wu_, Nov 18 2019 using b-file of A306360