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Simple continued fraction expansion of Gamma(exp(gamma)+1).
0

%I #23 Nov 05 2019 10:37:49

%S 1,1,1,1,6,15,1,4,2,1,11,2,3,1,1,13,1,1,1,1,5,1,27,1,37,1,1,2,2,2,40,

%T 1,3,1,5,1,1,3,3942,3,2,1,13,3,11,1,2,1,15,1,1,2,1,51,37,1,1,13,4,1,1,

%U 2,5,1,1,2,1,1,5,1,75,1,16,6,2,2,1,1,7,2,4

%N Simple continued fraction expansion of Gamma(exp(gamma)+1).

%C 'Gamma' is the gamma function, and 'gamma' is the Euler-Mascheroni constant.

%C Approximation of Gamma(exp(gamma)+1) in decimal: 1.6501566139104548059...

%F Gamma(exp(gamma)+1) = Gamma(exp(gamma)) * exp(gamma).

%t ContinuedFraction[Gamma[1 + Exp[EulerGamma]], 81] (* _Amiram Eldar_, Oct 13 2019 *)

%o (PARI) contfrac(gamma(exp(Euler)+1)) \\ _Michel Marcus_, Nov 04 2019

%Y Cf. A094644, A073004, A079650.

%K cofr,nonn

%O 0,5

%A _Daniel Hoyt_, Oct 12 2019