Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).
%I #22 Sep 19 2019 03:25:36
%S 3,1,2,3,3,1,2,1,3,2,1,2,3,1,2,1,2,3,3,1,2,3,2,1,2,1,3,3,1,2,3,3,1,2,
%T 1,2,3,2,1,3,3,1,2,3,3,1,2,1,3,2,1,2,3,3,1,2,1,2,3,1,2,1,3,2,1,2,1,3,
%U 3,1,2,3,2,1,3,3,2,1,2,1,3,3,1,2,3
%N For n >= 1, a(n) = b(n+1) - b(n) where b is A013947.
%C Stepwise answer to the stepwise question "How far ahead is the next 1 in the Kolakoski sequence, starting from A000002(1) = 1?" Sequence contains only 1s, 2s and 3s. Conjecture: Densities of 1s, 2s, and 3s -> 1/3 as n->infinity.
%F a(n) = A013947(n+1) - A013947(n); n >= 1.
%e n=1 -> a(1) = A013947(2) - A013947(1) = 4 - 1 = 3.
%Y Cf. A000002, A013947.
%K nonn
%O 1,1
%A _David James Sycamore_, Sep 14 2019