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a(n) = prime(n)^(n!).
5

%I #4 May 13 2019 08:12:04

%S 2,9,15625,191581231380566414401,

%T 92709068817830061978520606494193845859707401497097037749844778027824097442147966967457359038488841338006006032592594389655201

%N a(n) = prime(n)^(n!).

%C A subsequence of A325619 (numbers whose prime indices have reciprocal factorial sum equal to 1).

%t Table[Prime[n]^n!,{n,5}]

%Y Cf. A056239, A112798.

%Y Factorial numbers: A000142, A007489, A022559, A064986, A108731, A115944, A284605, A325508, A325616.

%Y Reciprocal factorial sum: A002966, A051908, A316855, A325618, A325619.

%K nonn

%O 1,1

%A _Gus Wiseman_, May 13 2019