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 A323624 The diagonal of the order of square grid cells touched by a circle expanding from the middle of a cell. 4
 0, 2, 5, 10, 16, 22, 32, 40, 50, 62, 73, 88, 101, 118, 134, 152, 170, 189, 210, 230, 253, 275, 299, 325, 351, 381, 406, 435, 465, 495, 527, 561, 593, 628, 663, 699, 737, 775, 813, 853, 895, 935, 981, 1021, 1068, 1113, 1156, 1205, 1253, 1302, 1352, 1401, 1454, 1502, 1557, 1609, 1664, 1723 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,2 COMMENTS Related to, but not the same as the case with the circle centered at the corner of a cell, see A232499. LINKS Table of n, a(n) for n=0..57. Rok Cestnik, Visualization PROG (Python) N = 12 from math import sqrt # the distance to the edge of each cell edges = [[-1 for j in range(N)] for i in range(N)] edges[0][0] = 0 for i in range(1, N): edges[i][0] = i-0.5 edges[0][i] = i-0.5 for i in range(1, N): for j in range(1, N): edges[i][j] = sqrt((i-0.5)**2+(j-0.5)**2) # the values of the distances values = [] for i in range(N): for j in range(N): values.append(edges[i][j]) values = list(set(values)) values.sort() # the cell order board = [[-1 for j in range(N)] for i in range(N)] count = 0 for v in values: for i in range(N): for j in range(N): if(edges[i][j] == v): board[i][j] = count count += 1 # print out the sequence for i in range(N): print(str(board[i][i])+", ", end="") CROSSREFS For the grid read by antidiagonals see A323621. For the first row of the grid see A323622. For the second row of the grid see A323623. For the (2,1) diagonal of the grid see A323625. Cf. A232499. Sequence in context: A243971 A062472 A135061 * A348387 A086849 A131938 Adjacent sequences: A323621 A323622 A323623 * A323625 A323626 A323627 KEYWORD nonn AUTHOR Rok Cestnik, Jan 20 2019 STATUS approved

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Last modified June 18 01:32 EDT 2024. Contains 373468 sequences. (Running on oeis4.)