%I #25 Jan 27 2019 09:02:09
%S 2700,5292,9000,13068,18252,24300,24500,24696,31212,38988,47628,55125,
%T 57132,60500,68600,84500,90828,95832,103788,117612,136125,144500,
%U 147852,158184,164268,166012,180500,181548,190125,199692,218700,231525,231868,238572,243000,264500,266200,280908,303372,325125
%N Numbers such that the list of exponents of their factorization is a palindromic list of primes.
%C I mean nontrivial palindrome: more than one number and not all equal numbers.
%C Factorization is meant to produce p1^e1*...*pk^ek, with pi in increasing order.
%e 9000 is a term as 9000=2^3*3^2*5^3 and the correspondent exponents list [3,2,3] is a palindromic list of primes.
%t aQ[s_] := Length[Union[s]]>1 && AllTrue[s, PrimeQ] && PalindromeQ[s]; Select[Range[1000], aQ[FactorInteger[#][[;;,2]]] &] (* _Amiram Eldar_, Dec 14 2018 *)
%o (Python)
%o from sympy.ntheory import factorint,isprime
%o def all_prime(l):
%o for i in l:
%o if not(isprime(i)): return(False)
%o return(True)
%o def all_equal(l):
%o ll=len(l)
%o set_l=set(l)
%o lsl=list(set_l)
%o llsl=len(lsl)
%o return(llsl==1)
%o def pal(l):
%o return(l == l[::-1])
%o n=350000
%o r=""
%o lp=[]
%o lexp=[]
%o def calc(n):
%o global lp,lexp
%o a=factorint(n)
%o lp=[]
%o for p in a.keys():
%o lp.append(p)
%o lexp=[]
%o for exp in a.values():
%o lexp.append(exp)
%o return
%o for i in range(4,n):
%o calc(i)
%o if len(lexp)>1:
%o if all_prime(lexp):
%o if not(all_equal(lexp)):
%o if pal(lexp):
%o r += ","+str(i)
%o print(r[1:])
%o (PARI) isok(n) = (ve=factor(n)[,2]~) && (Vecrev(ve)==ve) && (#ve>1) && (#Set(ve)>1) && (#select(x->(!isprime(x)), ve) == 0); \\ _Michel Marcus_, Dec 14 2018
%Y Subsequence of A242414.
%K nonn
%O 1,1
%A _Pierandrea Formusa_, Dec 13 2018