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%I #7 Oct 19 2018 17:01:16
%S 3,4,6,11,10,24,26,34,26,33,50,67,72,46,70,109,96,132,122,153,132,145,
%T 174,229,208,175,194,287,232,244,338,267,276,345,374,239,392,396,424,
%U 390,484,373,514,563,618,424,654,821,442,557,890,814,668,741,580,642,990,811,982,968,772
%N Sum of the square excess A056892 of the primes between two squares.
%C Consider the primes p1,...,pK between two squares n^2 and (n+1)^2, and take the sum of the differences: (p1 - n^2) + ... + (pK - n^2). Obviously this equals (sum of these primes) - (number of these primes) * n^2.
%F a(n) = A108314(n) - A014085(n)*A000290(n), where A000290(n) = n^2.
%o (PARI) a(n,s=0)={forprime(p=n^2,(n+1)^2,s+=p-n^2);s}
%Y Cf. A014085, A000290, A108314, A106044.
%Y Row sums of A056892, read as a table.
%Y Equals A108314 - A014085 * A000290.
%K nonn
%O 1,1
%A _M. F. Hasler_, Oct 19 2018