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A319847 Irregular triangle read by rows in which row n lists the odd divisors of n in increasing order together with the even divisors of n in increasing order. 7

%I #32 Nov 25 2019 10:55:18

%S 1,1,2,1,3,1,2,4,1,5,1,3,2,6,1,7,1,2,4,8,1,3,9,1,5,2,10,1,11,1,3,2,4,

%T 6,12,1,13,1,7,2,14,1,3,5,15,1,2,4,8,16,1,17,1,3,9,2,6,18,1,19,1,5,2,

%U 4,10,20,1,3,7,21,1,11,2,22,1,23,1,3,2,4,6,8,12,24,1,5,25,1,13,2,26,1,3,9,27

%N Irregular triangle read by rows in which row n lists the odd divisors of n in increasing order together with the even divisors of n in increasing order.

%C Consider the diagram with overlapping periodic curves that appears in the Links section (figure 1). The number of curves that contain the point [n,0] equals the number of divisors of n. The simpler interpretation of the diagram is that the curve of diameter d represents the divisor d of n. Now here we introduce a new interpretation: the curve of diameter d that contains the point [n,0] represents the divisor c of n, where c = n/d. This model has the property that each odd quadrant centered at [n,0] contains the curves that represent the even divisors of n, and each even quadrant centered at [n,0] contains the curves that represent the odd divisors of n.

%C We can find the n-th row of the triangle as follows:

%C Consider only the semicircumferences that contain the point [n,0].

%C In the second quadrant from top to bottom we can see the curves that represent the odd divisors of n in increasing order. Also we can see these curves in the fourth quadrant from bottom to top.

%C Then, if n is an even number, in the first quadrant from top to bottom we can see the curves that represent the even divisors of n in increasing order. Also we can see these curves in the third quadrant from bottom to top (see example).

%C Sequences of the same family are shown below:

%C -----------------------------------

%C Triangle Order of divisors of n

%C -----------------------------------

%C A299481 odd v t.w. even ^

%C A299483 odd ^ t.w. even v

%C A319844 even v t.w. odd ^

%C A319845 even ^ t.w. odd v

%C A319846 odd v t.w. even v

%C This seq. odd ^ t.w. even ^

%C A319848 even v t.w. odd v

%C A319849 even ^ t.w. odd ^

%C -----------------------------------

%C In the above table we have that:

%C "even v" means "even divisors of n in decreasing order".

%C "even ^" means "even divisors of n in increasing order".

%C "odd v" means "odd divisors of n in decreasing order".

%C "odd ^" means "odd divisors of n in increasing order".

%C "t.w." means "together with".

%H Omar E. Pol, <a href="http://www.polprimos.com/imagenespub/poldiv01.jpg">Figure 1: Geometric model of divisors with periodic curves (for n = 1..16)</a>, <a href="http://www.polprimos.com/imagenespub/poldiv02.jpg">figure 2: Upper part</a>, <a href="http://www.polprimos.com/imagenespub/poldiv03.jpg">figure 3: Lower part upside down.</a>

%H <a href="/index/Di#divisors">Index entries for sequences related to divisors of numbers</a>

%e Triangle begins:

%e 1;

%e 1, 2;

%e 1, 3;

%e 1, 2, 4;

%e 1, 5;

%e 1, 3, 2, 6;

%e 1, 7;

%e 1, 2, 4, 8;

%e 1, 3, 9;

%e 1, 5, 2, 10;

%e 1, 11;

%e 1, 3, 2, 4, 6, 12;

%e 1, 13;

%e 1, 7, 2, 14;

%e 1, 3, 5, 15;

%e 1, 2, 4, 8, 16;

%e 1, 17;

%e 1, 3, 9, 2, 6, 18;

%e 1, 19;

%e 1, 5, 2, 4, 10, 20;

%e 1, 3, 7, 21;

%e 1, 11, 2, 22;

%e 1, 23;

%e 1, 3, 2, 4, 6, 8, 12, 24;

%e 1, 5, 25;

%e 1, 13, 2, 26;

%e 1, 3, 9, 27;

%e 1, 7, 2, 4, 14, 28;

%e ...

%e For n = 12 the divisors of 12 are [1, 2, 3, 4, 6, 12]. The odd divisors of 12 in increasing order are [1, 3], and the even divisors of 12 in increasing order are [2, 4, 6, 12], so the 12th row of triangle is [1, 3, 2, 4, 6, 12].

%e On the other hand, consider the diagram that appears in the Links section (figure 1). Then consider only the semicircumferences that contain the point [12,0]. In the second quadrant, from top to bottom, we can see the curves with diameters [12, 4]. Also we can see these curves in the fourth quadrant from bottom to top. The associated numbers c = 12/d are [1, 3] respectively. These are the odd divisors of 12 in increasing order. Then, in the first quadrant, from top to bottom, we can see the curves with diameters [6, 3, 2, 1]. Also we can see these curves in the third quadrant from bottom to top. The associated numbers c = 12/d are [2, 4, 6, 12] respectively. These are the even divisors of n in increasing order. Finally all numbers c obtained are [1, 3, 2, 4, 6, 12] equaling the 12th row of triangle.

%o (PARI) row(n) = my(d=divisors(n)); concat(select(x->(x%2), d), select(x->!(x%2), d));

%o lista(nn) = {for (n=1, nn, my(r = row(n)); for (k=1, #r, print1(r[k], ", ")););} \\ _Michel Marcus_, Jan 17 2019

%Y A permutation of A027750 from which first differs at a(12) = T(6,2).

%Y Row sums give A000203.

%Y Row n has length A000005(n).

%Y Column 1 gives A000012.

%Y Right border gives A000027.

%Y Other permutations of A027750 are A056538, A210959, A299481, A299483, A319844, A319845, A319846, A319848, A319849.

%Y Cf. A001227, A183063, A299480, A299485.

%K nonn,tabf

%O 1,3

%A _Omar E. Pol_, Sep 29 2018

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