OFFSET
1,4
COMMENTS
The next value a(28) is either 15 or 16.
a(6k+1) = a(6k+2) = a(6k+3) = 3k+1 for k >= 1. This follows from the solution to Kirkman's schoolgirl problem with n schoolgirls.
The values of a(6k), a(6k-1) and a(6k-2) are either 3k or 3k+1.
LINKS
D. K. Ray-Chaudhuri and Richard M. Wilson, Solution of Kirkman's schoolgirl problem, in Proceedings of Symposia in Pure Mathematics, Volume 19, 1971.
Wikipedia, Kirkman's schoolgirl problem
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Floris P. van Doorn, Aug 25 2018
STATUS
approved