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a(n) = n*(n+1)*(n+3).
1

%I #43 Feb 22 2022 03:37:12

%S 0,8,30,72,140,240,378,560,792,1080,1430,1848,2340,2912,3570,4320,

%T 5168,6120,7182,8360,9660,11088,12650,14352,16200,18200,20358,22680,

%U 25172,27840,30690,33728,36960,40392,44030,47880,51948,56240,60762,65520,70520,75768,81270,87032

%N a(n) = n*(n+1)*(n+3).

%H Amiram Eldar, <a href="/A317637/b317637.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).

%F a(n) = 2*A077414(n+1).

%F Sum_{n>=1} 1/a(n) = 7/36. - _Amiram Eldar_, Oct 07 2020

%F Sum_{n>=1} (-1)^(n+1)/a(n) = 2*log(2)/3 - 13/36. - _Amiram Eldar_, Feb 22 2022

%t Table[n*(n + 1)*(n + 3), {n, 0, 43}] (* _Giovanni Resta_, Aug 10 2018 *)

%Y Cf. A077414.

%K nonn,easy

%O 0,2

%A _Renzo Remotti_, Aug 02 2018