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a(n) = n! * [x^n] 1/(1 - x)^exp(n*x).
1

%I #6 May 21 2019 02:26:29

%S 1,1,6,60,936,21495,681480,28157451,1455590528,91689831225,

%T 6907344210400,612700433073707,63107430169208832,7455570223877314721,

%U 999839697339310324224,150885818035154310155625,25434297819615665229168640,4758031551536565527014516561

%N a(n) = n! * [x^n] 1/(1 - x)^exp(n*x).

%t Table[n! SeriesCoefficient[1/(1 - x)^Exp[n x], {x, 0, n}], {n, 0, 17}]

%Y Cf. A190314, A191365, A308333.

%K nonn

%O 0,3

%A _Ilya Gutkovskiy_, May 20 2019