%I #10 Apr 23 2019 02:53:06
%S 1,1,0,0,0,1,1,0,0,0,1,3,0,6,0,27,13,59,390,661,4933,9760,49415,
%T 101967,341887,702884,2209559,5361004,15472531,34165997,82258594,
%U 193682533,490404772,1210929426,2725005202,6283337761,13672859806,34906926846
%N Number of partitions of n^4 into exactly n nonzero fourth powers.
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/BiquadraticNumber.html">Biquadratic Number</a>
%e 11^4 =
%e 1^4 + 2^4 + 2^4 + 4^4 + 4^4 + 4^4 + 4^4 + 6^4 + 8^4 + 8^4 + 8^4 =
%e 2^4 + 2^4 + 2^4 + 2^4 + 2^4 + 2^4 + 6^4 + 6^4 + 6^4 + 8^4 + 9^4 =
%e 2^4 + 2^4 + 2^4 + 4^4 + 6^4 + 6^4 + 6^4 + 6^4 + 6^4 + 6^4 + 9^4,
%e so a(11) = 3.
%Y Cf. A000583, A259793, A299169, A299195, A307643, A319435.
%K nonn
%O 0,12
%A _Ilya Gutkovskiy_, Apr 19 2019
%E a(20)-a(28) from _Vaclav Kotesovec_, Apr 20 2019
%E a(29)-a(37) from _Vaclav Kotesovec_, Apr 23 2019