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a(n) is the denominator of 1/2 - 1/(prime(n)+1), where prime(n) is the n-th prime.
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%I #15 Feb 19 2023 12:53:01

%S 6,4,3,8,12,7,9,20,24,15,32,19,21,44,48,27,60,31,68,72,37,80,84,45,49,

%T 51,104,108,55,57,128,132,69,140,75,152,79,164,168,87,180,91,192,97,

%U 99,200,212,224,228,115,117,240,121,252,129,264,135,272,139,141,284,147,308,312,157

%N a(n) is the denominator of 1/2 - 1/(prime(n)+1), where prime(n) is the n-th prime.

%H Nitya Mani and Simon Rubinstein-Salzedo, <a href="https://arxiv.org/abs/1902.09048">Diophantine Tuples over Zp</a>, arXiv:1902.09048 [math.NT], 2019. See Lemma 3.3. p. 4.

%t 1/2-1/(#+1)&/@Prime[Range[70]]//Denominator (* _Harvey P. Dale_, Feb 19 2023 *)

%o (PARI) a(n) = denominator(1/2 - 1/(prime(n)+1));

%o (Python)

%o from sympy import prime

%o from fractions import Fraction

%o def a(n): return (Fraction(1, 2) - Fraction(1, (prime(n)+1))).denominator

%o print([a(n) for n in range(1, 66)]) # _Michael S. Branicky_, Jun 04 2021

%Y Cf. A236965 (numerators).

%Y Cf. A145979 (denominator of 1/2 - 1/(n+1)).

%K nonn,frac

%O 1,1

%A _Michel Marcus_, Feb 26 2019