OFFSET

1,1

COMMENTS

R. G. Stanton found that a(2) = 257.

a(n) >= 73 for any n, see [Stanton].

There exist infinitely many Riesel numbers that are divisible by 15. The number 334437671621489828385689959795356586832846847109919809460835 is one such number.

REFERENCES

R. G. Stanton, Further results on covering integers of the form 1 + k * 2^n by primes, pp. 107-114 in: Kevin L. McAvaney (ed.), Combinatorial Mathematics VIII, Lecture Notes in Mathematics 884, Berlin: Springer, 1981.

LINKS

Carlos Rivera, Problem 49. Sierpinski-like numbers, The Prime Puzzles and Problems Connection.

FORMULA

a(((2*n-1)^b+1)/2) = a(n) for every b >= 2.

a((2*b-1)*n-b+1) >= a(n) for every b >= 2; n > 1.

a(n) = 73 if and only if gcd(2*n-1, 70050435) = 1.

EXAMPLE

Examples of the covering sets:

- for n = 2, the set is {5, 7, 11, 13, 17, 19, 31, 37, 41, 61, 73, 97, 109, 151, 241, 257},

- for n = 3, the set is {3, 7, 11, 13, 19, 31, 37, 41, 61, 73, 109, 151},

- for n = 4, the set is {3, 5, 11, 13, 19, 31, 37, 41, 61, 73, 151},

- for n = 6, the set is {3, 5, 7, 13, 19, 37, 73},

- for n = 7, the set is {3, 5, 7, 11, 19, 31, 37, 41, 61, 73, 151},

- for n = 8, the set is {7, 11, 13, 17, 19, 29, 31, 37, 41, 43, 61, 71, 73, 97, 109, 113, 127, 151, 193, 211, 241, 257, 281, 331, 337, 421, 433, 577, 673, 1153, 1321},

- for n = 11, the set is {5, 11, 13, 17, 19, 31, 37, 41, 61, 73, 97, 109, 151, 181, 193, 241, 257, 331, 433, 577, 631, 673, 1153, 1321},

- for n = 17, the set is {5, 7, 13, 17, 19, 31, 37, 41, 61, 73, 97, 109, 151, 241, 257, 331},

- for n = 18, the set is {3, 11, 13, 17, 19, 31, 37, 41, 61, 73, 97, 109, 151, 241, 257},

- for n = 20, the set is {5, 7, 11, 17, 19, 31, 37, 41, 61, 73, 97, 109, 151, 241, 257, 331},

- for n = 26, the set is {5, 7, 11, 13, 19, 31, 37, 41, 61, 73, 97, 109, 151, 241, 257, 331},

- for n = 28, the set is {3, 7, 13, 17, 19, 37, 73, 109, 241}.

CROSSREFS

KEYWORD

nonn

AUTHOR

Arkadiusz Wesolowski, Jun 02 2018

STATUS

approved