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Lengths of successive runs in A303599.
4

%I #13 Jun 03 2018 10:59:56

%S 1,1,3,2,8,1,3,1,4,1,1,1,1,1,30,1,7,1,2,1,32,1,5,1,11,1,1,1,1,1,1,1,1,

%T 1,7,1,10,1,68,1,11,1,9,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,6,1,

%U 2,1,3,1,7,1,7,1,129,1,8,1,30,1,4,1,5,1,1,1,1,1,5,1,1

%N Lengths of successive runs in A303599.

%C Created as part of a study to try to show that A252867 is a permutation, and, more specifically, to understand terms 6171 - 7025 of A252867 (see the graph of that sequence). This "brick" in the graph of A252867 corresponds to the exceptionally large term a(831) = 1824 of the current sequence.

%H N. J. A. Sloane, <a href="/A305368/b305368.txt">Table of n, a(n) for n = 1..5026</a>

%Y Cf. A252867, A303596, A303597, A303598, A303599.

%K nonn

%O 1,3

%A _N. J. A. Sloane_, May 31 2018