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A304314 Logarithmic derivative of F(x) that satisfies: [x^n] exp( n^4 * x ) / F(x) = 0 for n>0. 6

%I #19 Aug 31 2020 10:57:21

%S 1,225,229000,612243125,3367384031526,33056423981177346,

%T 527146092112494861420,12764850938355048224394925,

%U 446065249480005516657138106375,21615893741029073481369412949207860,1406758471936562034421316174257309550136,119755662436589797897149020637183902177930534

%N Logarithmic derivative of F(x) that satisfies: [x^n] exp( n^4 * x ) / F(x) = 0 for n>0.

%C Conjecture: a(n) is the number of connected n-state finite automata with 4 inputs.

%C Equals row 4 of table A304321.

%H Paul D. Hanna, <a href="/A304314/b304314.txt">Table of n, a(n) for n = 0..200</a>

%F Logarithmic derivative of the o.g.f. of A304324.

%F For n>=1, a(n) = B_{n+1}((n+1)^4-0!*a(0),-1!*a(1),...,-(n-1)!*a(n-1),0) / n!, where B_{n+1}(...) is the (n+1)-st complete exponential Bell polynomial. - _Max Alekseyev_, Jun 18 2018

%F a(n) ~ sqrt(1-c) * 4^(4*(n+1)) * n^(3*n + 7/2) / (sqrt(2*Pi) * c^(n+1) * (4-c)^(3*(n+1)) * exp(3*n)), where c = -LambertW(-4*exp(-4)). - _Vaclav Kotesovec_, Aug 31 2020

%e O.g.f.: L(x) = 1 + 225*x + 229000*x^2 + 612243125*x^3 + 3367384031526*x^4 + 33056423981177346*x^5 + 527146092112494861420*x^6 + ...

%e such that L(x) = F'(x)/F(x) where F(x) is the o.g.f. of A304324 :

%e F(x) = 1 + x + 113*x^2 + 76446*x^3 + 153143499*x^4 + 673638499100*x^5 + 5510097691767062*x^6 + 75312181798660695788*x^7 + ... + A304324(n)*x^n + ...

%e which satisfies [x^n] exp( n^4 * x ) / F(x) = 0 for n>0.

%t m = 25;

%t F = 1 + Sum[c[k] x^k, {k, m}];

%t s[n_] := Solve[SeriesCoefficient[Exp[n^4*x]/F, {x, 0, n}] == 0][[1]];

%t Do[F = F /. s[n], {n, m}];

%t CoefficientList[D[F, x]/F + O[x]^m, x] (* _Jean-François Alcover_, May 21 2018 *)

%o (PARI) {a(n) = my(A=[1],L); for(i=0, n, A=concat(A, 0); m=#A; A[m] = Vec( exp(x*(m-1)^4 +x^2*O(x^m)) / Ser(A) )[m] ); L = Vec(Ser(A)'/Ser(A)); L[n+1]}

%o for(n=0,25, print1( a(n),", "))

%Y Cf. A304324, A304321, A304312, A304313, A304315.

%K nonn

%O 0,2

%A _Paul D. Hanna_, May 11 2018

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