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Lengths of successive runs in A303598.
4

%I #13 Jun 03 2018 10:57:46

%S 4,2,1,1,1,2,2,1,1,1,1,1,1,1,1,2,1,1,1,2,1,1,1,1,2,1,2,1,2,1,1,1,1,1,

%T 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,1,1,1,1,1,1,1,2,

%U 1,1,2,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1

%N Lengths of successive runs in A303598.

%C Created as part of a study to try to show that A252867 is a permutation, and, more specifically, to understand terms 6171 - 7025 of A252867 (see the graph of that sequence).

%H N. J. A. Sloane, <a href="/A303599/b303599.txt">Table of n, a(n) for n = 1..47482</a>

%Y Cf. A252867, A303596, A303597, A303599, A305368.

%K nonn

%O 1,1

%A _N. J. A. Sloane_, May 31 2018