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A302932
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Sequence gives the denominators, in increasing values, of Egyptian fractions such that their sum has the concatenation of these denominators as decimal part. Case a(1) = 3.
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22
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OFFSET
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1,1
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COMMENTS
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There are only three possible sequences of this kind: one starting from 3 (this sequence), another from 4 (A304286) and another from 10 (A302933).
Next term a(8) has 152 digits (see b-file). - Giovanni Resta, Apr 16 2018
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LINKS
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EXAMPLE
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We start from 3 because 1/3 = 0.3333...
Then the next integer is 52 because 1/3 + 1/52 = 0.352564... and so on.
The sum is 0.3 52 58130 684605953 18209086488275508678 ...
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MAPLE
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P:=proc(q) local a, b, d, n; a:=1/3; b:=1; d:=3; print(d);
for n from 1 to q do if trunc(evalf(a+1/n, 100)*10^(b+ilog10(n)+1))=d*10^(ilog10(n)+1)+n then b:=b+ilog10(n)+1; d:=d*10^(ilog10(n)+1)+n; a:=a+1/n; print(n); fi;
od; end: P(10^20);
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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