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%I #5 Mar 29 2019 15:51:20
%S 1,1,0,1,-1,0,1,-1,1,0,1,-1,0,-2,0,1,-1,0,0,2,0,1,-1,0,-1,0,-3,0,1,-1,
%T 0,-1,2,-1,4,0,1,-1,0,-1,1,-2,1,-5,0,1,-1,0,-1,1,0,1,-1,6,0,1,-1,0,-1,
%U 1,-1,0,-2,1,-8,0,1,-1,0,-1,1,-1,2,-1,4,0,10,0,1,-1,0,-1,1,-1,1,-2,1,-4,0,-12,0
%N Square array A(n,k), n >= 0, k >= 1, read by antidiagonals, where column k is the expansion of Product_{j>=1} (1 + x^(k*j))/(1 + x^j).
%F G.f. of column k: Product_{j>=1} (1 + x^(k*j))/(1 + x^j).
%F For asymptotics of column k see comment from _Vaclav Kotesovec_ in A145707.
%e Square array begins:
%e 1, 1, 1, 1, 1, 1, ...
%e 0, -1, -1, -1, -1, -1, ...
%e 0, 1, 0, 0, 0, 0, ...
%e 0, -2, 0, -1, -1, -1, ...
%e 0, 2, 0, 2, 1, 1, ...
%e 0, -3, -1, -2, 0, -1, ...
%t Table[Function[k, SeriesCoefficient[Product[(1 + x^(k i))/(1 + x^i), {i, 1, n}], {x, 0, n}]][j - n + 1], {j, 0, 12}, {n, 0, j}] // Flatten
%t Table[Function[k, SeriesCoefficient[QPochhammer[-1, x^k]/QPochhammer[-1, x], {x, 0, n}]][j - n + 1], {j, 0, 12}, {n, 0, j}] // Flatten
%Y Columns k=1-10 give: A000007, A081360, A109389, A261734, A133563, A261736, A113297, A261735, A261733, A145707.
%Y Main diagonal gives A081362.
%Y Cf. A286653, A286656, A290307.
%K sign,tabl
%O 0,14
%A _Ilya Gutkovskiy_, Apr 03 2018