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A297141 Numbers having a down-first zigzag pattern in base 8; see Comments. 4

%I #7 Apr 11 2018 09:03:03

%S 8,16,17,24,25,26,32,33,34,35,40,41,42,43,44,48,49,50,51,52,53,56,57,

%T 58,59,60,61,62,65,66,67,68,69,70,71,129,130,131,132,133,134,135,136,

%U 138,139,140,141,142,143,193,194,195,196,197,198,199,200,202,203

%N Numbers having a down-first zigzag pattern in base 8; see Comments.

%C A number n having base-b digits d(m), d(m-1),..., d(0) such that d(i) != d(i+1) for 0 <= i < m shows a zigzag pattern of one or more segments, in the following sense. Writing U for up and D for down, there are two kinds of patterns: U, UD, UDU, UDUD, ... and D, DU, DUD, DUDU, ... . In the former case, we say n has an "up-first zigzag pattern in base b"; in the latter, a "down-first zigzag pattern in base b". Example: 2,4,5,3,0,1,4,2 has segments 2,4,5; 5,3,0; 0,1,4; and 4,2, so that 24530142, with pattern UDUD, has an up-first zigzag pattern in base 10, whereas 4,2,5,3,0,1,4,2 has a down-first pattern. The sequences A297140-A297142 partition the natural numbers. See the guide at A297146.

%e Base-8 digits of 4599: 1,0,7,6,7, with pattern DUDU, so that 4599 is in the sequence.

%t a[n_, b_] := Sign[Differences[IntegerDigits[n, b]]]; z = 300;

%t b = 8; t = Table[a[n, b], {n, 1, 10*z}];

%t u = Select[Range[z], ! MemberQ[t[[#]], 0] && First[t[[#]]] == 1 &] (* A297140 *)

%t v = Select[Range[z], ! MemberQ[t[[#]], 0] && First[t[[#]]] == -1 &] (* A297141 *)

%t Complement[Range[z], Union[u, v]] (* A297142 *)

%Y Cf. A297140, A297142.

%K nonn,easy,base

%O 1,1

%A _Clark Kimberling_, Jan 15 2018

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Last modified August 17 11:18 EDT 2024. Contains 375209 sequences. (Running on oeis4.)