login
Smallest average of a twin prime pair divisible by the n-th prime, i.e. A090530(n), divided by 6*prime(n).
3

%I #15 Nov 12 2017 09:36:01

%S 1,1,3,4,1,2,1,2,7,9,5,4,1,20,3,43,4,3,14,22,9,8,19,7,1,1,8,4,24,5,1,

%T 2,2,13,4,6,5,9,22,3,15,6,11,3,7,5,20,5,6,7,3,3,9,14,10,2,35,2,1,10,

%U 25,17,1,35,5,4,1,18,15,12,25,1,2,5

%N Smallest average of a twin prime pair divisible by the n-th prime, i.e. A090530(n), divided by 6*prime(n).

%C The sequence starts at n=3, because A090530(1)=4 is not divisible by 6*2 and A090530(2)=6 is not divisible by 6*3.

%C The positions of ones in the sequence are given by A060212, i.e. a(A000720(A060212(n)))=1 for all n>=3.

%H Hugo Pfoertner, <a href="/A294731/b294731.txt">Table of n, a(n) for n = 3..10000</a>

%F a(n) = A090530(n) / ( 6 * prime(n) ) for n >= 3.

%e a(5)=3 because 198 is the smallest average of a twin prime pair {197,199} that is divisible by the 5th prime 11: 3 = 198 / (6*11).

%Y Cf. A014574, A060212, A090530, A182481.

%K nonn

%O 3,3

%A _Hugo Pfoertner_, Nov 09 2017