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a(n) = (2*n + 4)!*(n^2 + 11*n + 2)/(2*(n-1)!*(n+6)!).
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%I #14 Nov 21 2017 02:46:56

%S 1,14,110,682,3731,18928,91392,426360,1939938,8662214,38119510,

%T 165828390,714707175,3056887680,12991772640,54919766160,231102342990,

%U 968661801900,4046295064812,16851791934516,69999056422526,290085110464864,1199652675300800,4951946963738320,20406434266878660

%N a(n) = (2*n + 4)!*(n^2 + 11*n + 2)/(2*(n-1)!*(n+6)!).

%H Robert Israel, <a href="/A294445/b294445.txt">Table of n, a(n) for n = 1..1655</a>

%H M. Bauer and O. Golinelli, <a href="https://arxiv.org/abs/cond-mat/0007127">Random incidence matrices: Moments of the spectral density</a>, arXiv:cond-mat/0007127 [cond-mat.stat-mech], 2000-2001; J. Stat. Phys. 103, 301-307 (2001). See Sect. 5.6.

%F From _Robert Israel_, Nov 20 2017: (Start)

%F G.f.: 128*x*(-22*x^2+sqrt(-4*x+1)+2*x+1)/((1+sqrt(-4*x+1))^8*(-4*x+1)^(3/2)).

%F (220+88*n)*a(n)+(-3248-734*n)*a(n+1)+(7030+1150*n)*a(n+2)+(-5606-731*n)*a(n+3)+(2068+226*n)*a(n+4)+(-360-34*n)*a(n+5)+(24+2*n)*a(n+6) = 0. (End)

%p seq( (2*n+4)!*(n^2+11*n+2)/(2*(n-1)!*(n+6)!), n=1..30); # _Robert Israel_, Nov 20 2017

%K nonn

%O 1,2

%A _N. J. A. Sloane_, Nov 20 2017