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a(n) = n! * [x^n] exp(n*tan(x)).
1

%I #6 Oct 06 2017 18:20:10

%S 1,1,4,33,384,5705,103392,2213225,54648832,1529006769,47806489600,

%T 1651929898641,62514008358912,2571311967708601,114219516618117120,

%U 5449390043986849305,277913379747357786112,15087434965491213149153,868698417435317196816384,52875073161897308106963585

%N a(n) = n! * [x^n] exp(n*tan(x)).

%F a(n) ~ c * d^n * n^n / exp(n), where d = 3.2897906634948022290195938576166779380... and c = 0.7144692216716261155107169918... - _Vaclav Kotesovec_, Oct 06 2017

%t Table[n! SeriesCoefficient[Exp[n Tan[x]], {x, 0, n}], {n, 0, 19}]

%Y Cf. A006229, A133941.

%K nonn

%O 0,3

%A _Ilya Gutkovskiy_, Sep 28 2017