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Numbers k such that 5 is the smallest decimal digit of k^3.
7

%I #16 Dec 06 2017 09:27:03

%S 19,423,1786,1966,4053,4235,40326,45882,198823,204782,442693,2131842,

%T 3911966,4061115,4081435,4603475,8789299,18027632,40987223,42647176,

%U 44100092,46097753,88776682,96439993,96540315,98954326,190349299,197967719,423185632,428896755,463968436

%N Numbers k such that 5 is the smallest decimal digit of k^3.

%C The first digit cannot be 5 or 6 and the last digit must be 2, 3, 5, 6, or 9. - _Chai Wah Wu_, Aug 28 2017

%C 92 is the smallest number such that 6 is the smallest decimal digit of its cube (92^3 = 778688). - _Chai Wah Wu_, Dec 05 2017

%H Giovanni Resta, <a href="/A291644/b291644.txt">Table of n, a(n) for n = 1..100</a>

%e 19 is in the sequence because 19^3 = 6859, the smallest decimal digit of which is 5.

%o (PARI) select(k->vecmin(digits(k^3))==5, vector(20000000, k, k))

%o (Python)

%o A291644_list = [k for k in range(1,10**6) if min(str(k**3)) == '5'] # _Chai Wah Wu_, Aug 28 2017

%Y Cf. A291639, A291640, A291641, A291642, A291643.

%K nonn,base

%O 1,1

%A _Colin Barker_, Aug 28 2017

%E a(19)-a(31) from _Chai Wah Wu_, Aug 28 2017