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A290842
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Numbers k such that the sum of digits of k^3 is 3^3 = 27.
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3
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27, 33, 36, 39, 42, 54, 57, 69, 72, 75, 78, 84, 87, 93, 105, 108, 111, 114, 135, 138, 147, 162, 165, 168, 174, 177, 219, 222, 225, 228, 231, 234, 258, 267, 270, 273, 276, 285, 291, 294, 312, 318, 321, 330, 342, 345, 348, 351, 360, 369, 381, 384, 390, 405, 417
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OFFSET
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1,1
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COMMENTS
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It is obvious that if k is in this sequence, then so is 10*k. Additionally, this sequence contains other infinite subsequences. For example, 10^(2*k) + 10^k + 1 is in this sequence for all k > 0. - Altug Alkan, Aug 12 2017
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LINKS
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EXAMPLE
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27^3 = 19683, 1 + 9 + 6 + 8 + 3 = 27 = 3^3.
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PROG
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(PARI) isok(n) = sumdigits(n^3) == 27; \\ Altug Alkan, Aug 12 2017
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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