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A290015 Brazilian numbers which have exactly two Brazilian representations. 4
15, 18, 21, 26, 28, 30, 31, 32, 44, 45, 50, 52, 56, 57, 62, 64, 68, 75, 76, 85, 86, 91, 92, 93, 98, 99, 110, 111, 116, 117, 129, 133, 146, 147, 148, 153, 164, 175, 183, 188, 207, 212, 215, 219, 236, 243, 244, 245, 259, 261, 268, 275, 279, 284, 314, 316, 325, 332, 338, 341, 343, 356, 363, 365, 369, 381, 387, 388 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
These numbers could be called 2-Brazilian numbers.
The smallest number of this sequence is 15 which is also the smallest odd composite Brazilian in A257521 with 15 = 11111_2 = 33_4. The number 15 is highly Brazilian in A329383.
Following the Goormaghtigh conjecture, only two primes, 31 and 8191, which are both Mersenne numbers, are Brazilian in two different bases (A119598).
LINKS
EXAMPLE
18 = 2 * 9 = 22_8 = 3 * 6 = 33_5.
26 = 2 * 13 = 2 * 111_3 = 222_3 = 22_12.
31 = 11111_2 = 111_5;
8191 = 1111111111111_2 = 111_90.
MAPLE
bresilienbaseb:=proc(n, b)
local r, q, coupleq:
if n<b then
return [1, n]
else
r:=(n mod b):
q:=(n-r)/b
coupleq:=bresilienbase(q, b):
if r=coupleq[2] and r>0 then
return [couple[1]+1, r]
else
return [0, 0]
end if
end if
end proc;
bresil:=proc(n)
local b, L, k, t:
k:=0:
for b from 2 to (n-2) do
t:=bresilienbase(n, b):
if t[1]>0 then
k:=k+1
L[k]:=[b, t[1], t[2]]:
end if:
end do:
seq(L[i], i=1..k);
end proc;
nbbresil:=n->nops([bresil(n)]);
#Numbers 2 times Brazilian
for n from 1 to 100 do if nbbresil(n)=2 then print(n, bresil(n)) else fi; od:
MATHEMATICA
Flatten@ Position[#, 2] &@ Table[Count[Range[2, n - 2], _?(And[Length@ # != 1, Length@ Union@ # == 1] &@ IntegerDigits[n, #] &)], {n, 400}] (* Michael De Vlieger, Jul 18 2017 *)
CROSSREFS
Sequence in context: A063779 A125006 A125008 * A354818 A274979 A083823
KEYWORD
nonn,base
AUTHOR
Bernard Schott, Jul 17 2017
STATUS
approved

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Last modified June 18 08:27 EDT 2024. Contains 373472 sequences. (Running on oeis4.)