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a(n) = Sum_{k=0..n} k!^4.
2

%I #17 Nov 29 2020 11:56:07

%S 1,2,18,1314,333090,207693090,268946253090,645510228813090,

%T 2643553803594573090,17342764866576345933090,

%U 173418555892594089945933090,2538940579958951120707545933090,52646414799433780559063261145933090,1503614384819523432725006336630745933090

%N a(n) = Sum_{k=0..n} k!^4.

%H Seiichi Manyama, <a href="/A289949/b289949.txt">Table of n, a(n) for n = 0..144</a>

%F a(n) = A289945(n) + 1 for n > 0.

%t Accumulate[(Range[0,15]!)^4] (* _Harvey P. Dale_, Nov 29 2020 *)

%o (PARI) a(n) = sum(k=0, n, k!^4); \\ _Michel Marcus_, Jul 16 2017

%Y Cf. A289945.

%Y Sum_{k=0..n} k!^m: A003422(n+1) (m=1), A061062 (m=2), A289948 (m=3), this sequence (m=4).

%K nonn

%O 0,2

%A _Seiichi Manyama_, Jul 16 2017