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%I #12 May 06 2021 09:21:40
%S 2,4,7,9,13,15,18,20,25,27,30,32,36,38,41,43,49,51,54,56,60,62,65,67,
%T 72,74,77,79,83,85,88,90,97,99,102,104,108,110,113,115,120,122,125,
%U 127,131,133,136,138,144,146,149,151,155,157,160,162,167,169,172
%N Positions of 0 in A288932; complement of A288934.
%C Conjecture: a(n)/n -> 3, and 0 < 3 - a(n)/n < 1 for n >= 1.
%H Clark Kimberling, <a href="/A288933/b288933.txt">Table of n, a(n) for n = 1..10000</a>
%F a(n) = 3*n-1-HammingWeight(n-1) = 3*n-1-A000120(n-1) (conjectured). - _Gleb Koloskov_, May 06 2021
%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];
%t w[n_] := StringReplace[w[n - 1], {"00" -> "1000", "1" -> "10101"}]
%t Table[w[n], {n, 0, 8}]
%t st = ToCharacterCode[w[11]] - 48 (* A288932 *)
%t Flatten[Position[st, 0]] (* A288933 *)
%t Flatten[Position[st, 1]] (* A288934 *)
%Y Cf. A288932, A288934, A000120.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, Jun 25 2017
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