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Positions of 0 in A288929; complement of A288931.
3

%I #4 Jun 25 2017 13:53:50

%S 2,3,6,9,10,15,16,19,24,25,28,31,32,39,40,43,46,47,52,53,56,63,64,67,

%T 70,71,76,77,80,85,86,89,92,93,102,103,106,109,110,115,116,119,124,

%U 125,128,131,132,139,140,143,146,147,152,153,156,165,166,169,172

%N Positions of 0 in A288929; complement of A288931.

%C Conjecture: a(n)/n -> 3, and 0 < m - a(n)/n < 3/2 for n >= 1.

%H Clark Kimberling, <a href="/A288930/b288930.txt">Table of n, a(n) for n = 1..10000</a>

%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];

%t w[n_] := StringReplace[w[n - 1], {"00" -> "1000", "1" -> "10011"}]

%t Table[w[n], {n, 0, 8}]

%t st = ToCharacterCode[w[11]] - 48 (* A288929 *)

%t Flatten[Position[st, 0]] (* A288930 *)

%t Flatten[Position[st, 1]] (* A288931 *)

%Y Cf. A288929, A288931.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Jun 25 2017