login
Positions of 0 in A288622; complement of A288624.
3

%I #4 Jun 15 2017 00:04:16

%S 1,2,4,6,9,10,12,15,16,18,21,22,24,25,27,28,30,32,35,36,38,41,42,44,

%T 45,47,48,50,52,55,56,58,61,62,64,65,67,68,70,72,75,76,78,79,81,83,86,

%U 87,89,90,92,94,97,98,100,103,104,106,109,110,112,113,115

%N Positions of 0 in A288622; complement of A288624.

%C Conjecture: a(n)/n->1.83..., and if m denotes this number, then -1 < m - a(n)/n) < 1 for n >= 1.

%H Clark Kimberling, <a href="/A288623/b288623.txt">Table of n, a(n) for n = 1..10000</a>

%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];

%t w[n_] := StringReplace[w[n - 1], {"00" -> "0110", "1" -> "01"}]

%t Table[w[n], {n, 0, 8}]

%t st = ToCharacterCode[w[10]] - 48 (* A288622 *)

%t Flatten[Position[st, 0]] (* A288623 *)

%t Flatten[Position[st, 1]] (* A288624 *)

%Y Cf. A288622, A288624.

%K nonn,easy

%O 1,2

%A _Clark Kimberling_, Jun 14 2017