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Positions of 0 in A288223; complement of A288225.
3

%I #9 Jun 25 2017 15:08:20

%S 1,3,5,6,7,8,9,11,13,14,15,16,18,19,20,22,23,25,27,28,29,30,31,33,34,

%T 36,38,39,40,42,43,44,45,47,49,50,51,52,54,55,56,58,59,61,63,64,65,66,

%U 68,70,71,72,73,74,76,77,78,80,81,83,85,86,87,89,90,91

%N Positions of 0 in A288223; complement of A288225.

%C Conjecture: a(n)/n -> 1.38..., and if m denotes this number, then -1 < m - a(n)/n < 1 for n >= 1.

%H Clark Kimberling, <a href="/A288224/b288224.txt">Table of n, a(n) for n = 1..10000</a>

%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];

%t w[n_] := StringReplace[w[n - 1], {"00" -> "1000", "10" -> "010"}]

%t Table[w[n], {n, 0, 8}]

%t st = ToCharacterCode[w[20]] - 48 (* A288223 *)

%t Flatten[Position[st, 0]] (* A288224 *)

%t Flatten[Position[st, 1]] (* A288225 *)

%Y Cf. A288223, A288225.

%K nonn,easy

%O 1,2

%A _Clark Kimberling_, Jun 19 2017