%I #4 May 13 2017 17:21:59
%S 1,3,4,6,9,10,12,13,15,18,19,21,22,24,25,27,30,31,33,34,36,39,40,42,
%T 43,45,46,48,51,52,54,55,57,60,61,63,64,66,69,70,72,73,75,76,78,81,82,
%U 84,85,87,90,91,93,94,96,97,99,102,103,105,106,108,111,112
%N Positions of 0 in A286691; complement of A286693.
%C a(n) - a(n-1) is in {1,2,3} for n>=2, and a(n)/n -> 4 - sqrt(8).
%H Clark Kimberling, <a href="/A286692/b286692.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A286691 = 0100101100100101100100100101100100..., in which 0 is in positions 1,3,4,6,9,...
%t s = Nest[Flatten[# /. {0 -> {0, 0, 1}, 1 -> {0}}] &, {0}, 6] (* A171588 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"0" -> "010", "1"->"110"}]
%t st = ToCharacterCode[w1] - 48 ; (* A286691 *)
%t Flatten[Position[st, 0]]; (* A286692 *)
%t Flatten[Position[st, 1]]; (* A286693 *)
%Y Cf. A171588, A286691, A286693.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 13 2017