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%I #4 May 09 2017 17:39:16
%S 2,5,6,9,11,14,16,17,20,23,24,27,29,30,33,36,38,41,42,45,47,50,52,53,
%T 56,59,61,64,65,68,70,71,74,77,78,81,83,86,88,89,92,95,96,99,101,102,
%U 105,108,110,113,114,117,119,120,123,126,127,130,132,135,137
%N Positions of 1 in A286339; complement of A286340.
%C a(n) - a(n-1) is in {1,2,3} for n>=2. Conjecture: a(n)/n -> 9/4.
%H Clark Kimberling, <a href="/A286341/b286341.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A286339 = 01001100101001011001001100..., in which 1 is in positions 2,5,6,9,11,...
%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0}}] &, {0}, 9] (* A010060 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"1101" -> "1"}]
%t st = ToCharacterCode[w1] - 48 (* A286339 *)
%t Flatten[Position[st, 0]] (* A286340 *)
%t Flatten[Position[st, 1]] (* A286341 *)
%Y Cf. A010060, A286339, A286340.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, May 09 2017
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