login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

Positions of 0 in A286046; complement of A286048.
4

%I #9 Apr 14 2022 15:05:13

%S 2,4,6,7,10,12,13,16,18,20,22,23,26,28,30,31,34,36,38,39,42,44,45,48,

%T 50,52,53,56,58,60,61,64,66,68,70,71,74,76,77,80,82,84,86,87,90,92,94,

%U 95,98,100,102,103,106,108,110,112,113,116,118,119,122,124

%N Positions of 0 in A286046; complement of A286048.

%C Conjecture: 2n - a(n) is in {0,1} for n >= 1.

%C From _Michel Dekking_, Apr 12 2022: (Start)

%C Obviously Kimberling's conjecture is equivalent to the property that A286046 is a concatenation of the two 2-blocks 01 and 10. This can be read off immediately from the {A, B, C, D} composition of A286046 given in the comments of that sequence.

%C But more is true. The first difference sequence (d(n)) = 2,2,1,3,2,1,3,... of (a(n)) is a morphic sequence. From the representation of A286046 by the decoration A->1010, B->1001, C->101001, D->10, we see that the differences between occurrences of 0's are given by a decoration:

%C A->22, B->13, C->213, D->2.

%C The 'natural' algorithm to obtain (d(n)) as a letter to letter image of a morphic sequence from this decoration yields (for example) a morphism mu on an alphabet {a,b,c,d,e,f} given by

%C mu: a->ab, b->cd, c->aed, d->f, e->cd, f->aed,

%C with the letter-to-letter map

%C lambda: a->2, b->2, c->1, d->3, e->1, f->2.

%C We have (d(n)) = lambda(z), where z is the fixed point z = abcdae... of mu.

%C (End)

%H Clark Kimberling, <a href="/A286047/b286047.txt">Table of n, a(n) for n = 1..10000</a>

%e As a word, A286046 = 101010011010011010..., in which 0 is in positions 2,4,6,7,10,...

%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0}}] &, {0}, 9] (* Thue-Morse, A010060 *)

%t w = StringJoin[Map[ToString, s]]

%t w1 = StringReplace[w, {"011" -> "1"}]

%t st = ToCharacterCode[w1] - 48 (* A286046 *)

%t Flatten[Position[st, 0]] (* A286047 *)

%t Flatten[Position[st, 1]] (* A286048 *)

%Y Cf. A010060, A286046, A286048.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, May 07 2017