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A285663 Positions of 1 in A285661; complement of A285662. 3

%I #4 May 02 2017 20:48:38

%S 1,2,5,6,9,10,11,12,13,14,17,18,21,22,23,24,25,26,29,30,33,34,37,38,

%T 41,42,45,46,49,50,51,52,53,54,57,58,61,62,63,64,65,66,69,70,73,74,77,

%U 78,81,82,85,86,89,90,91,92,93,94,97,98,101,102,103,104,105

%N Positions of 1 in A285661; complement of A285662.

%C Conjecture: a(n)/n -> (1 + sqrt(5))/2 = golden ratio (A001622).

%H Clark Kimberling, <a href="/A285663/b285663.txt">Table of n, a(n) for n = 1..10000</a>

%e As a word, A285661 = 110011001..., in which 1 is in positions 1,2,5,6,9,...

%t s = Nest[Flatten[# /. {0 -> {1, 1}, 1 -> {1, 1, 0, 0}}] &, {0}, 9] (* A285661 *)

%t Flatten[Position[s, 0]] (* A285662 *)

%t Flatten[Position[s, 1]] (* A285663 *)

%Y Cf. A285662, A285663.

%K nonn,easy

%O 1,2

%A _Clark Kimberling_, May 02 2017

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Last modified September 10 12:37 EDT 2024. Contains 375789 sequences. (Running on oeis4.)