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Positions of 0 in A285599; complement of A285601.
3

%I #4 May 01 2017 08:30:48

%S 3,7,11,17,21,25,29,33,39,43,47,53,57,61,67,71,75,79,83,89,93,97,103,

%T 107,111,117,121,125,129,133,139,143,147,153,157,161,167,171,175,181,

%U 185,189,195,199,203,207,211,217,221,225,231,235,239,245,249,253

%N Positions of 0 in A285599; complement of A285601.

%C Conjecture: a(n)/n -> (5+sqrt(17))/2.

%H Clark Kimberling, <a href="/A285600/b285600.txt">Table of n, a(n) for n = 1..10000</a>

%e As a word, A285599 = 11011101110..., in which 0 is in positions 3,7,11,17,...

%t s = Nest[Flatten[# /. {0 -> {1, 1}, 1 -> {0, 1, 1, 1}}] &, {0}, 11] (* A285599 *)

%t Flatten[Position[s, 0]] (* A285600 *)

%t Flatten[Position[s, 1]] (* A285601 *)

%Y Cf. A285596, A285599, A285601.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, May 01 2017