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%I #4 Apr 30 2017 22:38:06
%S 1,3,5,7,9,11,14,16,18,20,22,24,26,28,30,32,34,37,39,41,43,45,47,49,
%T 51,53,56,58,60,62,64,66,68,70,72,75,77,79,81,83,85,87,89,91,93,95,98,
%U 100,102,104,106,108,110,112,114,117,119,121,124,126,128,131
%N Positions of 0 in A285589; complement of A285591.
%C Conjecture: a(n)/n -> (1+sqrt(5/4).
%H Clark Kimberling, <a href="/A285590/b285590.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A285568 = 01010101010110..., in which 0 is in positions 1,3,5,7,...
%t s = Nest[Flatten[# /. {0 -> {1, 1}, 1 -> {0, 1, 1, 0}}] &, {0}, 8] (* A285565 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"00" -> "0", "11" -> "1"}]
%t ss = ToCharacterCode[w1] - 48 (* A285589 *)
%t Flatten[Position[ss, 0]] (* A285590 *)
%t Flatten[Position[ss, 1]] (* A285591 *)
%Y Cf. A285565, A285589, A285591, A285592.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, Apr 30 2017
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