%I #4 Apr 30 2017 11:30:09
%S 3,7,11,15,17,18,19,20,23,25,26,29,33,37,41,45,49,51,52,53,54,57,59,
%T 60,63,67,71,75,79,83,85,86,87,88,91,93,94,97,101,105,109,113,117,119,
%U 120,121,122,125,127,128,131,135,137,138,139,140,143,145,146,147
%N Positions of 1 in A285495; complement of A285496.
%H Clark Kimberling, <a href="/A285497/b285497.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A285495 = 00100010..., in which 1 is in positions 3,7,11,15,...
%t s = Nest[Flatten[# /. {0 -> {1, 1}, 1 -> {0, 0, 1, 0}}] &, {0}, 10] (* A285495 *)
%t Flatten[Position[s, 0]] (* A285496 *)
%t Flatten[Position[s, 1]] (* A285497 *)
%Y Cf. A285495, A285496, A285498.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, Apr 30 2017