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%I #4 Apr 18 2017 15:24:57
%S 1,4,8,11,14,18,22,25,28,32,35,38,42,45,48,52,56,59,62,66,70,73,76,80,
%T 83,86,90,93,96,100,104,107,110,114,117,120,124,127,130,134,138,141,
%U 144,148,151,154,158,161,164,168,172,175,178,182,186,189,192,196
%N Positions of 0 in A284929; complement of A284931.
%C Conjecture: 1 < n*r - a(n) < 4 for n >= 1, where r = 2 + sqrt(2).
%H Clark Kimberling, <a href="/A284930/b284930.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A284929 = 011011..., in which 0 is in positions 1,4,8,11,...
%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0, 1, 1}}] &, {0}, 6] (* A284929 *)
%t Flatten[Position[s, 0]] (* A284930 *)
%t Flatten[Position[s, 1]] (* A284931 *)
%Y Cf. A284929, A284931.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, Apr 18 2017
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