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%I #4 Apr 17 2017 08:58:50
%S 1,4,5,6,8,9,10,11,13,15,18,19,20,21,23,25,27,30,31,32,33,36,37,38,39,
%T 42,43,44,46,47,48,49,51,53,55,58,59,60,61,64,65,66,67,70,71,72,73,76,
%U 77,78,80,81,82,83,85,87,89,92,93,94,96,97,98,99,101,103
%N Positions of 0 in A284901; complement of A284903.
%C Conjecture: -3 < n*r - a(n) < 3 for n >= 1, where r = (3+sqrt(3))/3.
%H Clark Kimberling, <a href="/A284902/b284902.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A284901 = 01100010..., in which 0 is in positions 1,4,5,6,8,9,11,...
%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {0, 0, 1, 1}}] &, {0}, 6] (* A284901 *)
%t Flatten[Position[s, 0]] (* A284902 *)
%t Flatten[Position[s, 1]] (* A284903 *)
%Y Cf. A284901, A284903.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, Apr 16 2017
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