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%I #6 Apr 05 2017 05:37:21
%S 10,15,20,25,30,250,280,310,340,370,400,465,495,525,555,585,615,680,
%T 710,740,770,800,830,895,925,955,985,1015,1045,1110,1140,1170,1200,
%U 1230,1260,7990,8170,8350,8530,8710,8890,9280,9460,9640,9820,10000,10180,10570,10750
%N Fixed points of the transform A284803.
%e 310 is a term of the sequence because 310 in base 6 is 1234, its complement in base 3 is 4321 and the digit reverse is again 1234 that is 310 in base 10.
%p P:=proc(q,h) local a,b,k,n; for n from 1 to q do a:=convert(n,base,h); b:=0;
%p for k from 1 to nops(a) do a[k]:=h-1-a[k]; b:=h*b+a[k]; od; if b=n then print(n); fi; od; end: P(10^2,6);
%Y Cf. A035928, A284803.
%K nonn,base,easy
%O 1,1
%A _Paolo P. Lava_, Apr 03 2017
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