%I #4 Mar 28 2017 15:09:57
%S 1,4,5,6,7,10,11,14,15,18,19,22,23,24,25,28,29,32,33,34,35,38,39,42,
%T 43,44,45,48,49,52,53,54,55,58,59,62,63,66,67,70,71,72,73,76,77,80,81,
%U 82,83,86,87,90,91,94,95,98,99,100,101,104,105,108,109,110
%N Positions of 1 in A284369; complement of A284370.
%C Conjecture: -2 < n*sqrt(3) < 3 for n >= 1.
%H Clark Kimberling, <a href="/A284371/b284371.txt">Table of n, a(n) for n = 1..18271</a>
%e The first 10 letters of the word in A284369 are 1001111001, in which the positions of 1 are 1,4,5,6,7,10.
%t s = Nest[Flatten[# /. {0 -> {1}, 1 -> {1, 0, 0, 1}}] &, {0}, 9]; (* A284369 *)
%t Flatten[Position[s, 0]]; (* A284370 *)
%t Flatten[Position[s, 1]]; (* A284371 *)
%Y Cf. A284369, A284370.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, Mar 26 2017