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%I #6 Mar 26 2017 11:51:29
%S 2,4,8,10,14,16,19,21,24,26,30,32,36,38,41,43,46,48,52,54,58,60,63,65,
%T 69,71,75,77,80,82,86,88,92,94,97,99,102,104,108,110,114,116,119,121,
%U 124,126,130,132,136,138,141,143,147,149,153,155,158,160,164
%N Positions of 0 in A283966; complement of A284015.
%C Conjecture: -1 < n*r - a(n) < 3 for n >= 1, where r = (7+sqrt(17))/4.
%H Clark Kimberling, <a href="/A283967/b283967.txt">Table of n, a(n) for n = 1..10000</a>
%e The first 5 letters of the word in A282966 are 10101, in which the positions of 0 are 2,4.
%t s = Nest[Flatten[# /. {0 -> {1}, 1 -> {1, 0, 1, 0,1}}] &, {0}, 8] (* A283966 *)
%t Flatten[Position[s, 0]] (* A283967 *)
%t Flatten[Position[s, 1]] (* A284015 *)
%Y Cf. A283966, A284015.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, Mar 26 2017
