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Triangle read by rows: T(n,k) (n>=1, 2<=k<=n+1) is the number of k-sequences of balls colored with at most n colors such that exactly one ball is of a color seen previously in the sequence.
3

%I #28 Nov 20 2024 04:18:43

%S 1,2,6,3,18,36,4,36,144,240,5,60,360,1200,1800,6,90,720,3600,10800,

%T 15120,7,126,1260,8400,37800,105840,141120,8,168,2016,16800,100800,

%U 423360,1128960,1451520

%N Triangle read by rows: T(n,k) (n>=1, 2<=k<=n+1) is the number of k-sequences of balls colored with at most n colors such that exactly one ball is of a color seen previously in the sequence.

%C Number of k-sequences of balls colored with at most n colors such that exactly two balls are the same color as some other ball in the sequence (necessarily each other). - _Jeremy Dover_, Sep 26 2017

%H Jeremy Dover, <a href="/A281881/b281881.txt">Table of n, a(n) for n = 1..999</a>

%H Jeremy Dover, <a href="http://math.stackexchange.com/a/2109013/342250">Answer to Cumulative Distribution Function of Collision Counts</a>

%F T(n,k) = binomial(k,2)*n!/(n+1-k)!.

%F T(n,k) = n*T(n-1,k-1) + (k-1)*n!/(n+1-k)!.

%e n=1 => AA -> T(1,2) = 1.

%e n=2 => AA, BB -> T(2,2) = 2; AAB, ABA, BAA, BBA, BAB, ABB -> T(2,3) = 6.

%e Triangle starts:

%e 1

%e 2, 6

%e 3, 18, 36

%e 4, 36, 144, 240

%e 5, 60, 360, 1200, 1800

%e 6, 90, 720, 3600, 10800, 15120

%e 7, 126, 1260, 8400, 37800, 105840, 141120

%e 8, 168, 2016, 16800, 100800, 423360, 1128960, 1451520

%e 9, 216, 3024, 30240, 226800, 1270080, 5080320, 13063680, 16329600

%e 10, 270, 4320, 50400, 453600, 3175200, 16934400, 65318400, 163296000, 199584000

%t Table[Binomial[k, 2] n!/(n + 1 - k)!, {n, 8}, {k, 2, n + 1}] // Flatten (* _Michael De Vlieger_, Feb 02 2017 *)

%Y Columns of table:

%Y T(n,2) = A000027(n)

%Y T(n,3) = A028896(n)

%Y Other sequences in table:

%Y T(n,n+1) = A001286(n)

%Y T(n,n) = A001804(n), n>=2

%K nonn,tabl,changed

%O 1,2

%A _Jeremy Dover_, Feb 01 2017